at 11:41 PM
There are 4 Rivers and 3 Temples in the above form.
All the rivers are magical, moment a worshiper crosses a river with any number of flowers, it becomes double. (For eg 1 flower becomes 2 flowers, 2 become 4 and so on).
How many minimum number of flowers a worshiper needs 2 carry from beginning such that he offers equal number of flowers in all the three temples, and he is left with zero flowers at the end of fourth river.
Solve this ??
The Worshiper needs to carry 7 Flowers & offers 8 Flowers in each Temple.
7*2 = 14 (First River)
14-8 = 6 (First Temple)
6*2 = 12 (Second River)
12-8 = 4 (Second Temple)
4*2 = 8 (Third River)
8-8 = 0 (Third Temple)