A strange tradition is followed in an orthodox and undeveloped village. The chief of the village collects taxes from all the males of the village yearly. But it is the method of taking taxes that is interesting.
The taxes paid in the form of grains and every male should pay equal pounds corresponding to his age. In simpler terms, a man aged 10 years will have to pay 10 pounds of grains and a 20 years old will be paying 20 pounds of grain.
The chief stands on a riser containing 7 different weights next to a large 2 pan scale. As per the interesting custom, the chief can only weigh using three of the seven weights.
In such a scenario, can you calculate what must be the weights of the seven weights each and who is the oldest man the chief can measure using those weights?
What must be kept in mind before you start calculating through any method is that the weights can be put on both the pans.
So the weights - 1, 3, 7, 12, 43, 76, 102
The oldest man that can be weighed using these weights is a man aged 122 years
at 10:23 AM